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11y^2=-11y
We move all terms to the left:
11y^2-(-11y)=0
We get rid of parentheses
11y^2+11y=0
a = 11; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·11·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*11}=\frac{-22}{22} =-1 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*11}=\frac{0}{22} =0 $
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